sinusoidal wave travels along a string, The time fora particular point to move from maximum displacement to zero is 0.28 s. What re the (a) period and (b) frequency? (c) The wavelength is 1.4 m ; what is the wave specd?

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We start by noting that the motion of a point on the string is simple harmonic. In such motion, the displacement can be described by a cosine function. For a cosine function, moving from the maximum (cosine of zero phase, which is 1) to the equilibrium position (where the cosine is 0) takes one-quarter of a full cycle.

(a) The time for a quarter period is given as 0.28 s. Therefore, the full period T is

T = 4 × 0.28 s = 1.12 s.

(b) Frequency f is the reciprocal of the period:

f = 1/T = 1/1.12 s ≈ 0.89 Hz.

(c) The wave speed v is related to the wavelength λ and the period T by

v = wavelength / period = 1.4 m / 1.12 s ≈ 1.25 m/s.

Thus, the answers are:
 (a) Period T = 1.12 s,
 (b) Frequency f ≈ 0.89 Hz,
 (c) Wave speed v ≈ 1.25 m/s.
(a) The period is 1.12 seconds. (b) The frequency is approximately 0.89 Hz. (c) The wave speed is about 1.25 meters per second.

sinusoidal wave travels along a string, The time fora particular point to move from maximum displacement to zero is 0.28 s. What re the (a) period and (b) frequency? (c) The wavelength is 1.4 m ; what is the wave specd?

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