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Question 8 Factor completely: \( 3 x^{2}+7 x+4 \) Factored Expression \( =\underline{\text { Blank } 1} \)

Ask by Mills Weston. in the United States
Mar 10,2025

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The factored expression is \( (x+1)(3x+4) \).

Solución

1. Compute the product of the coefficient of \( x^2 \) and the constant term: \[ 3 \times 4 = 12. \] 2. Find two numbers that multiply to \( 12 \) and add to \( 7 \) (the coefficient of \( x \)). The numbers are \( 3 \) and \( 4 \). 3. Rewrite the middle term \( 7x \) as \( 3x+4x \): \[ 3x^2 + 3x + 4x + 4. \] 4. Factor by grouping: \[ \begin{aligned} 3x^2 + 3x + 4x + 4 &= 3x(x+1) + 4(x+1) \\ &= (x+1)(3x+4). \end{aligned} \] Thus, the factored expression is \( (x+1)(3x+4) \).

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Bonus Knowledge

To factor the quadratic expression \( 3x^2 + 7x + 4 \) completely, we look for two numbers that multiply to \( 3 \times 4 = 12 \) and add to \( 7 \). Those numbers are \( 3 \) and \( 4 \). We can then rewrite the equation as: \[ 3x^2 + 3x + 4x + 4 \] Now, grouping the terms gives us: \[ (3x^2 + 3x) + (4x + 4) \] Factoring out the common factors from each group results in: \[ 3x(x + 1) + 4(x + 1) \] Since \( (x + 1) \) is a common factor, we factor it out: \[ (3x + 4)(x + 1) \] So, the completely factored expression is: \[ \underline{(3x + 4)(x + 1)} \] --- Did you know that factoring quadratics like this goes back to ancient civilizations? The Babylonians were among the first to solve quadratic equations, using geometric methods long before algebra was formalized. They had some serious math skills for their time! For real-world application, factoring quadratics can help in many practical scenarios, like determining the projectile motion of objects. If you are designing a rollercoaster, for instance, understanding the factors can help optimize the ride's height and speed, ensuring safety while maximizing thrill!

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