The acidity of a solution is measured by its pH . If \( \left[\mathrm{H}^{+}\right] \)represents the concentration of hydrogen ions (in moles/liter) in the solution, the pH is defined by Suppose a solution has \( \mathrm{pH}=2.28 \). \( \mathrm{pH}=-\log \left[\mathrm{H}^{+}\right] \) (a) Rewrite the logarithmic form of the equation into exponential form. ( \( \Leftrightarrow \) indicates two way equivalence) - \( \log \left[\mathrm{H}^{+}\right]=\mathrm{pH} \Leftrightarrow \) Click for List \( \left[\mathrm{H}^{+}\right] \approx 0.00263 \) moles/liter \( \left[\mathrm{H}^{+}\right] \approx 2.7938 \) moles/liter \( \left[\mathrm{H}^{+}\right] \approx 0.00525 \) moles/liter \( \left[\mathrm{H}^{+}\right] \approx-190.5461 \) moles/liter \( \left[\mathrm{H}^{+}\right] \approx 0.4386 \) moles/liter \( \left[\mathrm{H}^{+}\right] \approx-0.3579 \) moles/liter \( \left[\mathrm{H}^{+}\right] \approx 0.3579 \) moles/liter

To solve the problem, we need to follow these steps: 1. **Rewrite the logarithmic form into exponential form**: The equation given is: \[ \text{pH} = -\log \left[\mathrm{H}^{+}\right] \] This can be rewritten in exponential form as: \[ \left[\mathrm{H}^{+}\right] = 10^{-\text{pH}} \] 2. **Substitute the given pH value**: We are given that \(\text{pH} = 2.28\). We can substitute this value into the exponential form: \[ \left[\mathrm{H}^{+}\right] = 10^{-2.28} \] 3. **Calculate the concentration of hydrogen ions**: Now, we will calculate \(10^{-2.28}\) to find the concentration \(\left[\mathrm{H}^{+}\right]\). Let's perform the calculation. Calculate the value by following steps: - step0: Calculate: \(10^{-2.28}\) - step1: Convert the expressions: \(10^{-\frac{57}{25}}\) - step2: Express with a positive exponent: \(\frac{1}{10^{\frac{57}{25}}}\) - step3: Simplify: \(\frac{1}{100\sqrt[25]{10^{7}}}\) - step4: Multiply by the Conjugate: \(\frac{\sqrt[25]{10^{18}}}{100\sqrt[25]{10^{7}}\times \sqrt[25]{10^{18}}}\) - step5: Multiply the numbers: \(\frac{\sqrt[25]{10^{18}}}{1000}\) The calculation gives us: \[ \left[\mathrm{H}^{+}\right] \approx 0.005248 \text{ moles/liter} \] Now, let's summarize the results: - The exponential form of the equation is: \[ \left[\mathrm{H}^{+}\right] = 10^{-\text{pH}} \Leftrightarrow \left[\mathrm{H}^{+}\right] \approx 0.00525 \text{ moles/liter} \] Thus, the correct answer from the options provided is: \[ \left[\mathrm{H}^{+}\right] \approx 0.00525 \text{ moles/liter} \]