The half-life of radium is 1690 years. If 90 grams are present now, how much will be present in 650 years? \( \square \) grams (Do not round until the final answer. Then round to the nearest thousandth as needed.)
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To find out how much radium will be present after 650 years, we can use the formula: \[ N_t = N_0 \left( \frac{1}{2} \right)^{\frac{t}{t_{1/2}}} \] Where: - \( N_t \) is the remaining quantity after time \( t \), - \( N_0 \) is the initial quantity (90 grams), - \( t \) is the elapsed time (650 years), - \( t_{1/2} \) is the half-life (1690 years). Plugging in the values, we get: \[ N_t = 90 \left( \frac{1}{2} \right)^{\frac{650}{1690}} \] Now we calculate: 1. First, find \( \frac{650}{1690} \approx 0.384 \). 2. Next, calculate \( \left( \frac{1}{2} \right)^{0.384} \approx 0.759 \). 3. Finally, multiply by the initial amount: \[ N_t \approx 90 \times 0.759 \approx 68.319 \text{ grams}. \] So, after rounding to the nearest thousandth, the amount of radium present will be approximately **68.319 grams**.
