Find the product. \[ (7-4 z)(7+4 z) \] \( (7-4 z)(7+4 z)=\square \) \( ( \) Simplify your answer. \( ) \)

To find the product \( (7-4z)(7+4z) \), we can use the difference of squares formula, which states that \( (a-b)(a+b) = a^2 - b^2 \). Here, let \( a = 7 \) and \( b = 4z \). Thus, we have: \[ (7-4z)(7+4z) = 7^2 - (4z)^2 \] Calculating each term, we find: \[ 7^2 = 49 \quad \text{and} \quad (4z)^2 = 16z^2 \] Now, substituting back into the equation gives us: \[ (7-4z)(7+4z) = 49 - 16z^2 \] So, the simplified answer is: \[ (7-4z)(7+4z) = 49 - 16z^2 \]