Ms. Smith puts a variety of wrapped chocolate candies into a bag. There are 5 silver - wrapped candies, 1 purple-wrapped candy, 2 striped candies, and 4 gold-wrapped candie If 15 students select one candy at a time out of the bag without looking, and replace the candy after each draw, how many students would be expected to select a gold-wrapped candy from the bag?

To find out how many students would be expected to select a gold-wrapped candy, we first need to determine the total number of candies in the bag. Ms. Smith has: - 5 silver-wrapped candies - 1 purple-wrapped candy - 2 striped candies - 4 gold-wrapped candies This gives us a total of 5 + 1 + 2 + 4 = 12 candies. Now, the probability of selecting a gold-wrapped candy is the number of gold-wrapped candies divided by the total number of candies, which is 4 (gold) / 12 (total) = 1/3. If 15 students are selecting candies, the expected number of students to select a gold-wrapped candy is 15 * (1/3) = 5. So, you would expect about 5 students to select a gold-wrapped candy from the bag. Expectations are key when assessing probabilities like this—good luck in your future candy draws! Also, it’s worth noting that depending on the approach to this distribution (like varying bag contents), the numbers can shift and surprise you. It’s like a candy mix; expect the unexpected!