\( 1600-5 x+0 {} \frac{1+\operatorname{Cin} A}{1-\tan A}=\frac{\operatorname{Cos} A+\operatorname{Sen} A}{\operatorname{Cos} A-\operatorname{Sin} A} \)
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Beyond the Answer
The equation you've presented is a mix of algebraic manipulation and trigonometric identities. Understanding the relationships between sine, cosine, and tangent can simplify this expression greatly. For instance, remember that \( \tan A = \frac{\sin A}{\cos A} \), allowing you to rewrite the terms. This will help you isolate \( A \) more easily. If you ever get tangled up in trigonometric identities, try drawing a right triangle and labeling the sides according to the angles involved. Visualizing the relationship can help clarify how to manipulate sine, cosine, and tangent effectively, allowing you to avoid common mistakes like misapplying relationships or missing negative signs!
