Part 1 of 2 Suppose the pH of a solution decreases by 8 . How does the hydrogen ion concentration change? The new hydrogen ion concentration is $$ \square $$ times the initial concentration. 0 of 1 (Use scientific notation. Use the multiplication symbol in the math palette as needed.)

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Let the initial pH be $$ p $$, so the initial hydrogen ion concentration is  
$$
[H^+]_{\text{initial}} = 10^{-p}.
$$

When the pH decreases by 8, the new pH is  
$$
p_{\text{new}} = p - 8.
$$

The new hydrogen ion concentration is then  
$$
[H^+]_{\text{new}} = 10^{-(p-8)} = 10^{8} \times 10^{-p}.
$$

To find how many times greater the new concentration is compared to the initial concentration, compute the ratio:  
$$
\frac{[H^+]_{\text{new}}}{[H^+]_{\text{initial}}} = \frac{10^{8} \times 10^{-p}}{10^{-p}} = 10^{8}.
$$

Thus, the new hydrogen ion concentration is $$ 10^{8} $$ times the initial concentration.
The new hydrogen ion concentration is $$ 10^{8} $$ times the initial concentration.

Part 1 of 2 Suppose the pH of a solution decreases by 8 . How does the hydrogen ion concentration change? The new hydrogen ion concentration is \( \square \) times the initial concentration. 0 of 1 (Use scientific notation. Use the multiplication symbol in the math palette as needed.)

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