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TRUE-H \( چ \) 10:43 \( 25 \% \) quizizz.com 13th โบน้ส 3 10/24 ข้อมูลชุดหนึ่งมีการแจกแจงปกติ มีค่า เฉลี่ยเลขคณิตและความแปรปรวน เท่ากับ 125 และ 25 ตามลำดับ ถ้าค่า มาตรฐานของข้อมูลตัวหนึ่งเท่ากับ 2 จงหาว่าข้อมูลตัวนั้นเท่ากับเท่าใด 25 200 135 50 175

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Feb 28,2025

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ข้อมูลตัวนั้นเท่ากับ 135

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ข้อมูลที่มีการแจกแจงปกติและมีค่าเฉลี่ยเลขคณิต (mean) ที่ 125 และความแปรปรวน (variance) ที่ 25 จะมีค่าเบี่ยงเบนมาตรฐาน (standard deviation) เท่ากับ 5 (เพราะหาค่าเบี่ยงเบนมาตรฐานได้จากการถอดรากที่สองของความแปรปรวน) ดังนั้นข้อมูลตัวหนึ่งที่มีค่าเบี่ยงเบนมาตรฐานเท่ากับ 2 จะมีค่าเกินหรือค่าน้อยกว่าเฉลี่ย 2 * 5 = 10 ดังนั้นข้อมูลตัวนั้นจะมีค่าเท่ากับ 125 + 10 = 135 หรือ 125 - 10 = 115 ข้อมูลที่ให้มาคือค่าตัวเลือก 135 และจะเป็นคำตอบที่ถูกต้องค่ะ! เพียงแค่ยกตัวอย่างการคำนวณเกี่ยวกับการแจกแจงปกติ การใช้ค่าเฉลี่ยและความแปรปรวนแบบปกตินี้สามารถนำไปใช้ในหลายๆ ด้าน เช่นในการวิเคราะห์ข้อมูลเพื่อหาค่ามาตรฐานหรือประเมินความเสี่ยงในทางการเงินหรือสถิติได้อย่างมีประสิทธิภาพ! หากคุณต้องการเรียนรู้เพิ่มเติมเกี่ยวกับการแจกแจงปกติและการวิเคราะห์ข้อมูล คุณอาจจะสนใจหนังสือเกี่ยวกับสถิติหรือการวิเคราะห์ข้อมูล เช่น "Naked Statistics" โดย Charles Wheelan ที่จะทำให้คุณเข้าใจแนวคิดต่าง ๆ ได้สนุกและเป็นกันเองมากขึ้น!

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