1.2. Gegee die getalle 45 en \( 60: 1 \) Given the numbers 45 and 60 : 1.2.1. Skryf elk van die bogenoende geatalle as 'n produk van hul priemfaktore del gebruik te maak van priem faktorisecring.' Write each of the numbers ahove as a product of its prime factors by using prime factorization.

To express the numbers 45 and 60 as a product of their prime factors, we will perform prime factorization for each number step by step. ### Step 1: Prime Factorization of 45 1. Start with the number 45. 2. Divide by the smallest prime number, which is 2. Since 45 is odd, we move to the next prime number, which is 3. 3. \( 45 \div 3 = 15 \) 4. Now, factor 15. Again, divide by 3. 5. \( 15 \div 3 = 5 \) 6. The number 5 is a prime number. Thus, the prime factorization of 45 is: \[ 45 = 3^2 \times 5 \] ### Step 2: Prime Factorization of 60 1. Start with the number 60. 2. Divide by the smallest prime number, which is 2. 3. \( 60 \div 2 = 30 \) 4. Now, factor 30. Divide by 2 again. 5. \( 30 \div 2 = 15 \) 6. Now, factor 15. Divide by 3. 7. \( 15 \div 3 = 5 \) 8. The number 5 is a prime number. Thus, the prime factorization of 60 is: \[ 60 = 2^2 \times 3 \times 5 \] ### Summary - The prime factorization of 45 is: \[ 45 = 3^2 \times 5 \] - The prime factorization of 60 is: \[ 60 = 2^2 \times 3 \times 5 \]