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Solve for \( x \) : \( \begin{array}{ll}\text { (1) } 7+9 x=7 x-3 & \text { (2) }-9+2 x=6-x \\ \text { (3) }-6(1-x)=10-2 x & \text { (4) } 9(x-3)=5(x-1)-14 \\ \text { (5) } \frac{2}{3}(x+2)-\frac{x+1}{5}=3 & \text { (6) } \frac{x-1}{2}-\frac{x+6}{3}=-2 \\ \text { (7) } x(x-2)+1=(x-2)^{2} & \text { (8) } \\ (x+2)(x-2)=(x+3)^{2}\end{array} \)

Ask by Carter Floyd. in South Africa
Mar 14,2025

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The solutions are: 1. \( x = -5 \) 2. \( x = 5 \) 3. \( x = 2 \) 4. \( x = 2 \) 5. \( x = 4 \) 6. \( x = 3 \) 7. \( x = \frac{3}{2} \) 8. \( x = -\frac{13}{6} \)

Solución

**(1)** Solve \[ 7+9x=7x-3. \] Subtract \(7x\) from both sides: \[ 7+2x=-3. \] Subtract 7 from both sides: \[ 2x=-10. \] Divide by 2: \[ x=-5. \] **(2)** Solve \[ -9+2x=6-x. \] Add \(x\) to both sides: \[ -9+3x=6. \] Add 9 to both sides: \[ 3x=15. \] Divide by 3: \[ x=5. \] **(3)** Solve \[ -6(1-x)=10-2x. \] Distribute \(-6\): \[ -6+6x=10-2x. \] Add \(2x\) to both sides: \[ -6+8x=10. \] Add 6 to both sides: \[ 8x=16. \] Divide by 8: \[ x=2. \] **(4)** Solve \[ 9(x-3)=5(x-1)-14. \] Distribute on both sides: \[ 9x-27=5x-5-14. \] Simplify the right-hand side: \[ 9x-27=5x-19. \] Subtract \(5x\) from both sides: \[ 4x-27=-19. \] Add 27 to both sides: \[ 4x=8. \] Divide by 4: \[ x=2. \] **(5)** Solve \[ \frac{2}{3}(x+2)-\frac{x+1}{5}=3. \] Multiply every term by the least common denominator (15): \[ 15\cdot\frac{2}{3}(x+2)-15\cdot\frac{x+1}{5}=15\cdot3. \] This simplifies to: \[ 5\cdot2(x+2)-3(x+1)=45. \] \[ 10(x+2)-3(x+1)=45. \] Expand: \[ 10x+20-3x-3=45. \] Combine like terms: \[ 7x+17=45. \] Subtract 17: \[ 7x=28. \] Divide by 7: \[ x=4. \] **(6)** Solve \[ \frac{x-1}{2}-\frac{x+6}{3}=-2. \] Multiply every term by the least common denominator (6): \[ 6\cdot\frac{x-1}{2}-6\cdot\frac{x+6}{3}=6\cdot(-2). \] Simplify: \[ 3(x-1)-2(x+6)=-12. \] \[ 3x-3-2x-12=-12. \] Combine like terms: \[ x-15=-12. \] Add 15 to both sides: \[ x=3. \] **(7)** Solve \[ x(x-2)+1=(x-2)^2. \] Expand both sides: \[ x^2-2x+1=x^2-4x+4. \] Subtract \(x^2\) from both sides: \[ -2x+1=-4x+4. \] Add \(4x\) to both sides: \[ 2x+1=4. \] Subtract 1: \[ 2x=3. \] Divide by 2: \[ x=\frac{3}{2}. \] **(8)** Solve \[ (x+2)(x-2)=(x+3)^2. \] Expand both sides: \[ x^2-4=x^2+6x+9. \] Subtract \(x^2\) from both sides: \[ -4=6x+9. \] Subtract 9 from both sides: \[ -13=6x. \] Divide by 6: \[ x=-\frac{13}{6}. \]

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Extra Insights

Alright, let’s dive into these equations and find the value of \( x \) for each one! 1. For the equation \( 7 + 9x = 7x - 3 \): - Rearranging gives \( 9x - 7x = -3 - 7 \) -> \( 2x = -10 \) -> \( x = -5 \). 2. For \( -9 + 2x = 6 - x \): - Rearranging gives \( 2x + x = 6 + 9 \) -> \( 3x = 15 \) -> \( x = 5 \). 3. For \( -6(1 - x) = 10 - 2x \): - Distributing gives us \( -6 + 6x = 10 - 2x \) -> \( 6x + 2x = 10 + 6 \) -> \( 8x = 16 \) -> \( x = 2 \). 4. For \( 9(x - 3) = 5(x - 1) - 14 \): - Expanding yields \( 9x - 27 = 5x - 5 - 14 \) -> \( 9x - 27 = 5x - 19 \) -> \( 9x - 5x = -19 + 27 \) -> \( 4x = 8 \) -> \( x = 2 \). 5. For \( \frac{2}{3}(x + 2) - \frac{x + 1}{5} = 3 \): - Multiply through by 15 (LCM of 3 and 5) to eliminate fractions: \( 10(x + 2) - 3(x + 1) = 45 \). - This simplifies to \( 10x + 20 - 3x - 3 = 45 \) -> \( 7x + 17 = 45 \) -> \( 7x = 28 \) -> \( x = 4 \). 6. For \( \frac{x - 1}{2} - \frac{x + 6}{3} = -2 \): - Multiply through by 6 (LCM of 2 and 3): \( 3(x - 1) - 2(x + 6) = -12 \). - This simplifies to \( 3x - 3 - 2x - 12 = -12 \) -> \( x - 15 = -12 \) -> \( x = 3 \). 7. For \( x(x - 2) + 1 = (x - 2)^{2} \): - Expanding gives us \( x^2 - 2x + 1 = x^2 - 4x + 4 \) -> \( -2x + 1 = -4x + 4 \). - Rearranging gives \( 4x - 2x = 4 - 1 \) -> \( 2x = 3 \) -> \( x = \frac{3}{2} \). 8. For \( (x + 2)(x - 2) = (x + 3)^{2} \): - Expanding leads us to \( x^2 - 4 = x^2 + 6x + 9 \) -> \( -4 = 6x + 9 \). - Rearranging yields \( 6x = -13 \) -> \( x = -\frac{13}{6} \). To summarize: 1. \( x = -5 \) 2. \( x = 5 \) 3. \( x = 2 \) 4. \( x = 2 \) 5. \( x = 4 \) 6. \( x = 3 \) 7. \( x = \frac{3}{2} \) 8. \( x = -\frac{13}{6} \)

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