(c) \( h(x)=\frac{2}{x} \) \( \frac{h(x+h)}{h}=\frac{2}{x+h}= \)
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The Deep Dive
When you substitute \( h \) into the function \( h(x+h) \), you essentially shift the input value of \( x \) to \( x + h \), which corresponds to the function output \( \frac{2}{x+h} \). Dividing by \( h \) keeps it as a fraction, allowing you to investigate the limit as \( h \) approaches zero. This is critical in calculus for finding derivatives, particularly the derivative of the function \( h(x) \). However, be careful not to make a common mistake here! Trying to evaluate directly by plugging in \( h = 0 \) can lead to undefined expressions. Instead, applying the limit process helps you deal effectively with those pesky \( h \)'s, leading you to the derivative of \( h(x) \) when examining \( \lim_{h \to 0} \frac{h(x+h) - h(x)}{h} \).
