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Convert the equation \( \rho=7 \) to rectangular coordinates and write in standard form.

Ask by Alexander Ellis. in the United States
Mar 08,2025

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The equation \( \rho = 7 \) in rectangular coordinates is \( x^2 + y^2 = 49 \).

Solución

To convert the equation \( \rho = 7 \) from polar to rectangular coordinates, we can use the relationship between polar and rectangular coordinates. In polar coordinates, \( \rho \) represents the distance from the origin, and in rectangular coordinates, we have: \[ x = \rho \cos(\theta) \] \[ y = \rho \sin(\theta) \] The equation \( \rho = 7 \) indicates that the distance from the origin is constant at 7. This describes a circle centered at the origin with a radius of 7. To express this in rectangular coordinates, we can use the equation: \[ \rho^2 = x^2 + y^2 \] Substituting \( \rho = 7 \) into this equation gives: \[ 7^2 = x^2 + y^2 \] Calculating \( 7^2 \): \[ 49 = x^2 + y^2 \] Now, we can write this in standard form: \[ x^2 + y^2 = 49 \] Thus, the equation \( \rho = 7 \) in rectangular coordinates and in standard form is: \[ x^2 + y^2 = 49 \]

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Bonus Knowledge

To convert the equation \( \rho = 7 \) to rectangular coordinates, we start by recognizing that in polar coordinates, \( \rho \) represents the radial distance from the origin. Hence, \( \rho = 7 \) indicates all points that are exactly 7 units away from the origin. In rectangular coordinates, this translates to the equation of a circle. Specifically, the standard form of a circle's equation is given by \[ (x - h)^2 + (y - k)^2 = r^2 \] where \( (h, k) \) is the center of the circle and \( r \) is its radius. Here, the center of our circle is at the origin \( (0, 0) \) and the radius \( r \) is 7. Substituting these values into the formula, we get: \[ x^2 + y^2 = 7^2 \] Simplifying this gives us: \[ x^2 + y^2 = 49 \] So the equation \( \rho = 7 \) in rectangular coordinates is \( x^2 + y^2 = 49 \) and this represents a circle with a radius of 7 centered at the origin.

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