e) \( 5^{\frac{2}{3}} \div\left(\frac{1}{25}\right)^{-0.2} \)
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First step is to simplify \( 5^{\frac{2}{3}} \). This can be rewritten as \( \sqrt[3]{5^2} = \sqrt[3]{25} \). Now, for the other part, \( \left(\frac{1}{25}\right)^{-0.2} \) can be rewritten as \( 25^{0.2} \) since \( a^{-b} = \frac{1}{a^b} \). Since \( 25 = 5^2 \), we get \( (5^2)^{0.2} = 5^{2 \cdot 0.2} = 5^{0.4} \). So now we’re dealing with \[ \frac{5^{\frac{2}{3}}}{5^{0.4}}. \] Using the property of exponents \( a^m \div a^n = a^{m-n} \): \[ 5^{\frac{2}{3} - 0.4} = 5^{\frac{2}{3} - \frac{4}{10}} = 5^{\frac{2}{3} - \frac{12}{30}} = 5^{\frac{20}{30} - \frac{12}{30}} = 5^{\frac{8}{30}} = 5^{\frac{4}{15}}. \] Thus, the final answer is \( 5^{\frac{4}{15}} \).
