The function $$ h $$ is defined below. $$ h(x) \frac{x^{2}+4 x+3}{x^{2}+8 x+16} $$ Find all values of $$ x $$ that are NOT in the domain of $$ h $$. If there is more than one value, separate them with commas. $$ x=\square . \square $$

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1. The function is given by  
   $$
   h(x)=\frac{x^2+4x+3}{x^2+8x+16}.
   $$

2. The domain of $$ h $$ consists of all real numbers except those values of $$ x $$ for which the denominator is zero.

3. Set the denominator equal to zero and solve:
   $$
   x^2 + 8x + 16 = 0.
   $$

4. Factor the quadratic. Notice that:
   $$
   x^2 + 8x + 16 = (x+4)^2.
   $$

5. Set the factor equal to zero:
   $$
   (x+4)^2 = 0 \quad \Longrightarrow \quad x+4 = 0 \quad \Longrightarrow \quad x = -4.
   $$

6. Therefore, the only value that is not in the domain of $$ h $$ is  
   $$
   x = -4.
   $$
$$ x = -4 $$

The function \( h \) is defined below. \[ h(x) \frac{x^{2}+4 x+3}{x^{2}+8 x+16} \] Find all values of \( x \) that are NOT in the domain of \( h \). If there is more than one value, separate them with commas. \( x=\square . \square \)

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