\[ \frac{v+9}{3}=8 \] Solve each equation. Fill in the missing number. \( \square \) \} Check \[ 2(n+5)=-2 \] Solve each equation. Fill in the missing number \{- \( \square \) \} Check \[ -9 x+1=-80 \] Solve each equation. Fill in the missing number. \( \{ \) \( \square \)
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To solve the first equation \(\frac{v+9}{3}=8\), we start by multiplying both sides by 3 to eliminate the fraction: \[ v+9 = 24 \] Next, we subtract 9 from both sides: \[ v = 15 \] So, the missing number is \(15\). For the second equation \(2(n+5)=-2\), we first divide both sides by 2: \[ n+5 = -1 \] Then, we subtract 5 from both sides: \[ n = -6 \] Thus, the missing number is \(-6\). Now for the third equation \(-9x+1=-80\), let's first subtract 1 from both sides: \[ -9x = -81 \] Next, we divide both sides by -9: \[ x = 9 \] Therefore, the missing number is \(9\). So summarizing: First Missing Number: \(15\), Second Missing Number: \(-6\), Third Missing Number: \(9\).
