Pregunta
Simplify \( \sqrt{(a+b)^{2}} \) \( a^{2}+b^{2} \) \( a b \) \( a+b \)
Ask by Simpson Delgado. in the United States
Feb 28,2025
Solución de inteligencia artificial de Upstudy
Respuesta verificada por el tutor
Responder
Here are the simplified forms:
1. √((a + b)²) = |a + b|
2. a² + b² remains as a² + b²
3. ab remains as ab
4. a + b remains as a + b
Solución
We are given four separate expressions to simplify. Here’s how to simplify each one:
1. √((a + b)²)
The square root of a square is the absolute value. In general, for any real number x, √(x²) = |x|. Thus,
√((a + b)²) = |a + b|.
2. a² + b²
The sum a² + b² is already in its simplest form. (Note that unless additional conditions or factorizations involving complex numbers are considered, there is no simpler real form.)
3. ab
The product ab is already as simple as it can be.
4. a + b
The sum a + b is also already in simplest form.
So the simplified forms are:
• √((a + b)²) = |a + b|
• a² + b² remains as a² + b²
• ab remains as ab
• a + b remains as a + b
Respondido por UpStudy AI y revisado por un tutor profesional
Como
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Extra Insights
The expression \( \sqrt{(a+b)^{2}} \) simplifies to \( |a+b| \), meaning the absolute value of \( a+b \). This is because when you take the square root of a squared term, you have to consider both the positive and negative roots. Make sure to remember that if \( a+b \) is a negative number, the square root will still give you a positive result, which is crucial in maintaining the function's integrity across all possible values of \( a \) and \( b \)!
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