Multiply. Assume all expressions are defined. \( \begin{array}{l}\frac{4 x+16}{2 x+6} \cdot \frac{x^{2}+2 x-3}{x+4} \\ 2(x-1) \\ 4(x-1) \\ 8(x-1) \\ 4(x+1)\end{array} \)

To simplify the expression, let's break it down step by step. First, factor all parts where possible: 1. **Numerator of the first fraction**: \(4x + 16 = 4(x + 4)\). 2. **Denominator of the first fraction**: \(2x + 6 = 2(x + 3)\). 3. **Numerator of the second fraction**: \(x^2 + 2x - 3\) factors to \((x + 3)(x - 1)\). Now, rewrite the entire expression: \[ \frac{4(x + 4)}{2(x + 3)} \cdot \frac{(x + 3)(x - 1)}{(x + 4)} \] Next, we can cancel out \( (x + 4) \) from the numerator and the denominator. We also cancel \( (x + 3) \): \[ \frac{4 \cancel{(x + 4)}}{2 \cancel{(x + 3)}} \cdot \frac{\cancel{(x + 3)}(x - 1)}{\cancel{(x + 4)}} \] This reduces to: \[ \frac{4(x - 1)}{2} \] Then, simplify \(\frac{4}{2} = 2\): \[ 2(x - 1) \] Lastly, the final answer is: \[ \boxed{2(x - 1)} \]