Solve the simultaneous equation \( \begin{array}{l}7 x+2 y=33 \\ 4 x+2 y=24\end{array} \)

To solve the simultaneous equations: 1. \( 7x + 2y = 33 \) (Equation 1) 2. \( 4x + 2y = 24 \) (Equation 2) First, we can eliminate \(2y\) by subtracting Equation 2 from Equation 1: \[ (7x + 2y) - (4x + 2y) = 33 - 24 \] This simplifies to: \[ 3x = 9 \] Now solve for \(x\): \[ x = \frac{9}{3} = 3 \] Now that we have \(x\), we can substitute it back into Equation 2 to find \(y\): \[ 4(3) + 2y = 24 \] This becomes: \[ 12 + 2y = 24 \] Now isolate \(2y\): \[ 2y = 24 - 12 \] \[ 2y = 12 \] Then solve for \(y\): \[ y = \frac{12}{2} = 6 \] Therefore, the solution to the simultaneous equations is \(x = 3\) and \(y = 6\).