What is the volume of the parallelepiped defined by the vectors \( \left[\begin{array}{c}-2 \\ 4 \\ 8\end{array}\right],\left[\begin{array}{c}-8 \\ 5 \\ 0\end{array}\right],\left[\begin{array}{l}0 \\ 2 \\ 9\end{array}\right] \) Volume \( = \) Ex. 1
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To find the volume of the parallelepiped defined by the vectors \( \mathbf{a} = \left[\begin{array}{c}-2 \\ 4 \\ 8\end{array}\right] \), \( \mathbf{b} = \left[\begin{array}{c}-8 \\ 5 \\ 0\end{array}\right] \), and \( \mathbf{c} = \left[\begin{array}{c}0 \\ 2 \\ 9\end{array}\right] \), you can use the scalar triple product. The volume \( V \) is given by the absolute value of the determinant of the matrix formed by these vectors: \[ V = |\mathbf{a} \cdot (\mathbf{b} \times \mathbf{c})| \] Calculating \( \mathbf{b} \times \mathbf{c} \): \[ \mathbf{b} \times \mathbf{c} = \left[\begin{array}{c} 5 \cdot 9 - 0 \cdot 2 \\ 0 \cdot 0 - (-8) \cdot 9 \\ (-8) \cdot 2 - 5 \cdot 0 \end{array}\right] = \left[\begin{array}{c} 45 \\ 72 \\ -16 \end{array}\right] \] Now, find \( \mathbf{a} \cdot (\mathbf{b} \times \mathbf{c}) \): \[ \mathbf{a} \cdot (\mathbf{b} \times \mathbf{c}) = (-2)(45) + (4)(72) + (8)(-16) = -90 + 288 - 128 = 70 \] Thus, the volume of the parallelepiped is: \[ V = |70| = 70 \] So the volume \( = 70 \) cubic units.
