There are three circular tabletops with diameters of $$ 5 \mathrm{ft}, 7 \mathrm{ft} $$, and 9 ft . Identify the area of each table top rounded to the nearest tenth. $$ A_{1} \approx 78.5 \mathrm{ft}^{2} ; A_{2} \approx 153.9 \mathrm{ft}^{2} ; A_{3}=254.5 \mathrm{ft}^{2} $$ $$ A_{1} \approx 15.7 \mathrm{ft}^{2} ; A_{2} \approx 22 \mathrm{ft}^{2} ; A_{3}=28.3 \mathrm{ft}^{2} $$ $$ A_{1} \approx 19.6 \mathrm{ft}^{2} ; A_{2} \approx 38.5 \mathrm{ft}^{2} ; A_{3}=63.6 \mathrm{ft}^{2} $$ $$ A_{1} \approx 31.4 \mathrm{ft}^{2} ; A_{2} \approx 44 \mathrm{ft}^{2} ; A_{3}=56.5 \mathrm{ft}^{2} $$

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The area of a circle is given by the formula

$$
A = \pi r^2,
$$

where $$ r $$ is the radius of the circle. Since the radius is half of the diameter, for each table we compute:

1. For the 5 ft table:
   - Radius: $$ r = \frac{5}{2} = 2.5 $$ ft.
   - Area:

$$
A_1 = \pi (2.5)^2 = \pi (6.25) \approx 19.6 \, \text{ft}^2.
$$

2. For the 7 ft table:
   - Radius: $$ r = \frac{7}{2} = 3.5 $$ ft.
   - Area:

$$
A_2 = \pi (3.5)^2 = \pi (12.25) \approx 38.5 \, \text{ft}^2.
$$

3. For the 9 ft table:
   - Radius: $$ r = \frac{9}{2} = 4.5 $$ ft.
   - Area:

$$
A_3 = \pi (4.5)^2 = \pi (20.25) \approx 63.6 \, \text{ft}^2.
$$

Thus, the areas rounded to the nearest tenth are:

$$
A_{1} \approx 19.6 \, \text{ft}^{2} ; \quad A_{2} \approx 38.5 \, \text{ft}^{2} ; \quad A_{3} \approx 63.6 \, \text{ft}^{2}.
$$

Comparing with the options given, the correct choice is:

$$
A_{1} \approx 19.6 \, \text{ft}^{2} ; \quad A_{2} \approx 38.5 \, \text{ft}^{2} ; \quad A_{3} \approx 63.6 \, \text{ft}^{2}.
$$
The areas of the table tops are approximately 19.6 ft², 38.5 ft², and 63.6 ft² respectively.

There are three circular tabletops with diameters of ,
and 9 ft . Identify the area of each table top rounded to the
nearest tenth.

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There are three circular tabletops with diameters of , and 9 ft . Identify the area of each table top rounded to the nearest tenth.