Malh 1 RdMut Clater Readil Qreale: logini.rready. 6om/gtudent/dashboard/hene ifready Solve Systems of Linear Equationsi Substitut Solve the system of equations. \[ \begin{array}{l} x=3 y-7 \\ y=x+1 \longrightarrow y=3 y-7+1 \end{array} \]

To solve this system of equations, we start with the first equation, \( x = 3y - 7 \). We can substitute this expression for \( x \) into the second equation \( y = x + 1 \), which gives us \( y = (3y - 7) + 1 \). Simplifying this leads to \( y = 3y - 6 \), and rearranging terms gives \( 2y = 6 \), so \( y = 3 \). Now, plug \( y \) back into the first equation to find \( x \): \( x = 3(3) - 7 = 9 - 7 = 2 \). Therefore, the solution to the system of equations is \( x = 2 \) and \( y = 3 \). If you find yourself getting tangled up in substitution, remember to clearly label each equation and substitute step by step. One common mistake is to forget to distribute or combine like terms accurately. Double-check every step to help catch these errors early!