Find all the zeros. Write the answer in exact form. \[ c(x)=2 x^{4}-1 x^{3}-26 x^{2}+37 x-12 \] If there is more than one answer, separate thern with commas. Select "None" if applicable. The zeros of \( c(x): \)

To find the zeros of the polynomial \( c(x)=2x^4 - x^3 - 26x^2 + 37x - 12 \), we can use the Rational Root Theorem, synthetic division, or numerical methods. Testing a few rational roots with possible factors of the constant term and leading coefficient leads us to discover that \( x = 3, x = 2, x = -1, \) and \( x = \frac{2}{2} \) are the zeros of \( c(x) \). Thus, the exact form of the zeros of \( c(x) \) is: \( 3, 2, -1, \frac{2}{2} \). Note: You would simplify \( \frac{2}{2} \) to \( 1 \) to reflect standard practices, making the list \( 3, 2, -1, 1 \).