Pregunta
Re-write the quadratic function below in Standard Form \( y=-3(x+4)^{2}+8 \)
Ask by Moran Hardy. in the United States
Feb 19,2025
Solución de inteligencia artificial de Upstudy
Respuesta verificada por el tutor
Responder
The quadratic function in standard form is \( y = -3x^{2} - 24x - 40 \).
Solución
Simplify the expression by following steps:
- step0: Add the terms:
\(-3\left(x+4\right)^{2}+8\)
- step1: Expand the expression:
\(-3x^{2}-24x-48+8\)
- step2: Add the numbers:
\(-3x^{2}-24x-40\)
To rewrite the quadratic function \( y = -3(x+4)^{2} + 8 \) in standard form, we first expand the expression.
1. Start with the given function:
\[
y = -3(x+4)^{2} + 8
\]
2. Expand \( (x+4)^{2} \):
\[
(x+4)^{2} = x^{2} + 8x + 16
\]
3. Substitute this back into the equation:
\[
y = -3(x^{2} + 8x + 16) + 8
\]
4. Distribute \(-3\):
\[
y = -3x^{2} - 24x - 48 + 8
\]
5. Combine like terms:
\[
y = -3x^{2} - 24x - 40
\]
Thus, the quadratic function in standard form is:
\[
y = -3x^{2} - 24x - 40
\]
Respondido por UpStudy AI y revisado por un tutor profesional
Como
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The Deep Dive
To rewrite the quadratic function \( y=-3(x+4)^{2}+8 \) in standard form, we first need to expand the expression. Begin by squaring \( (x+4) \): \[ (x+4)^2 = x^2 + 8x + 16. \] Now substitute this into the equation: \[ y = -3(x^2 + 8x + 16) + 8. \] Distributing the \(-3\): \[ y = -3x^2 - 24x - 48 + 8. \] Combining the constants: \[ y = -3x^2 - 24x - 40. \] Now, the quadratic function in standard form \( y = ax^2 + bx + c \) is: \[ y = -3x^2 - 24x - 40. \]
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