e) \( -20 \cdot 3-80: 20= \) f) \( -21:(-3)-[4 \cdot(-8)+1]= \) g) \( 4 \cdot 3+8:-2= \) h) \( 1-2:[2-3 \cdot 15-16:(-4)]-2= \)

To solve your equations step by step: e) \( -20 \cdot 3 - 80 : 20 \) First, calculate \( -20 \cdot 3 = -60 \). Then, do \( 80 : 20 = 4 \). Finally, \( -60 - 4 = -64 \). f) \( -21 : (-3) - [4 \cdot (-8) + 1] \) Start with \( -21 : (-3) = 7 \). Next, compute \( 4 \cdot (-8) = -32 \), so \( -32 + 1 = -31 \). Finally, \( 7 - (-31) = 7 + 31 = 38 \). g) \( 4 \cdot 3 + 8 : -2 \) Calculate \( 4 \cdot 3 = 12 \) first. Then, \( 8 : -2 = -4 \). Hence, \( 12 - 4 = 8 \). h) \( 1 - 2 : [2 - 3 \cdot 15 - 16 : (-4)] - 2 \) Inside the brackets, calculate \( 3 \cdot 15 = 45 \), so \( 2 - 45 - 16 : (-4) \). Then, \( 16 : (-4) = -4 \), making it \( 2 - 45 + 4 = -39 \). Now substitute back: \( 1 - 2 : (-39) - 2 \). Thus, \( 2 : (-39) = -\frac{2}{39} \), so \( 1 + \frac{2}{39} - 2 \) gives \( -1 + \frac{2}{39} = -\frac{39}{39} + \frac{2}{39} = -\frac{37}{39} \). So, the answers are: e) -64 f) 38 g) 8 h) -\(\frac{37}{39}\)