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A rectangular room is 4 times as long as it is wide, and its perimeter is 50 meters. Find the dimension of the room. The length is :

Ask by Barnett Hardy. in the United States
Mar 16,2025

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The length of the room is 20 meters.

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The width of the room can be represented as \( w \), making the length \( 4w \). The perimeter of a rectangle is calculated as \( 2(\text{length} + \text{width}) \). Plugging in the given values, we have: \[ 2(4w + w) = 50 \] Simplifying gives us: \[ 10w = 50 \] This means \( w = 5 \) meters. Therefore, the length, which is \( 4w \), would be \( 4 \times 5 = 20 \) meters. To reaffirm your finding, the equation checks out with the perimeter: \( 2(20 + 5) = 50 \) meters, thus confirming the dimensions. The length is: 20 meters.

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