Which of the following is the solution of the system \[ \begin{array}{l}-2 x-4 y=0 \\ -6 x+3 y=45\end{array} \] Select the correct answer below: \( (-9,-3) \) \( (-10,5) \) \( (-6,3) \) \( (-2,1) \) \( \left(\begin{array}{l}-4) \\ \left(\begin{array}{l}-2\end{array}\right)\end{array}\right. \)

Consider the system: \[ \begin{aligned} -2x - 4y &= 0 \quad (1) \\ -6x + 3y &= 45 \quad (2) \end{aligned} \] **Step 1:** Solve equation \((1)\) for \(x\). Divide equation \((1)\) by \(-2\): \[ x + 2y = 0 \quad \Rightarrow \quad x = -2y. \] **Step 2:** Substitute \(x = -2y\) into equation \((2)\). \[ -6(-2y) + 3y = 45. \] Simplify: \[ 12y + 3y = 45. \] Combine like terms: \[ 15y = 45. \] **Step 3:** Solve for \(y\). \[ y = \frac{45}{15} = 3. \] **Step 4:** Substitute \(y = 3\) back into \(x = -2y\). \[ x = -2(3) = -6. \] The solution of the system is: \[ (x, y) = (-6, 3). \] Thus, the correct answer is \((-6, 3)\).