Determine if the given planes are parallel, perpendicular, or neither. \( \begin{array}{l}-2 x+2 y-4 z+5=0 \\ 4 x-4 y+8 z-5=0 \\ \checkmark \text { Select } \\ \text { Parallel } \\ \text { Neither } \\ \text { Perpendicular }\end{array} \)

To determine the relationship between the two planes, we need to look at their normal vectors. The normal vector of the first plane \( -2x + 2y - 4z + 5 = 0 \) is given by \((-2, 2, -4)\), and the normal vector of the second plane \( 4x - 4y + 8z - 5 = 0 \) is \((4, -4, 8)\). First, check for parallelism: Two planes are parallel if their normal vectors are scalar multiples of each other. In this case, the second normal vector \((4, -4, 8)\) is indeed a scalar multiple of the first one \((-2, 2, -4)\) since \(4 = -2 \times (-2)\), \(-4 = 2 \times (-2)\), and \(8 = -4 \times (-2)\). This indicates that the planes are parallel. Therefore, the answer is: **Parallel**