Solve for \( y \), where \( y \) is a real number. \[ 1=\sqrt{4 y+16}-1 \] If there is more than one solution, separate them with commas. If there is no solution, click on "No solution".

To solve the equation \( 1 = \sqrt{4y + 16} - 1 \), we first isolate the square root: \[ 1 + 1 = \sqrt{4y + 16} \] This simplifies to: \[ 2 = \sqrt{4y + 16} \] Next, we square both sides to eliminate the square root: \[ 2^2 = 4y + 16 \] So we have: \[ 4 = 4y + 16 \] Now, we can isolate \( y \) by subtracting 16 from both sides: \[ 4 - 16 = 4y \] This simplifies to: \[ -12 = 4y \] Now, we divide both sides by 4: \[ y = -3 \] Thus, the solution for \( y \) is: \[ \boxed{-3} \]