Pregunta
Factor by grouping. Select "Prime" if the polynomial cannot be factored. \( 4 b^{5}+12 b^{2}-5 b^{3}-15=\square \) \( \square \)
Ask by Rodriguez Warren. in the United States
Mar 12,2025
Solución de inteligencia artificial de Upstudy
Respuesta verificada por el tutor
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The factored form is \((4b^{2}-5)(b^{3}+3)\).
Solución
Factor the expression \( 4b^5+12b^2-5b^3-15 \).
Factor the expression by following steps:
- step0: Factor:
\(4b^{5}+12b^{2}-5b^{3}-15\)
- step1: Rewrite the expression:
\(4b^{2}\times b^{3}+4b^{2}\times 3-5b^{3}-5\times 3\)
- step2: Factor the expression:
\(4b^{2}\left(b^{3}+3\right)-5\left(b^{3}+3\right)\)
- step3: Factor the expression:
\(\left(4b^{2}-5\right)\left(b^{3}+3\right)\)
The factored form of the given polynomial \(4b^{5}+12b^{2}-5b^{3}-15\) is \((4b^{2}-5)(b^{3}+3)\).
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Como
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Bonus Knowledge
To factor the polynomial \( 4b^5 + 12b^2 - 5b^3 - 15 \) by grouping, we can rearrange the terms as \( (4b^5 - 5b^3) + (12b^2 - 15) \). Factoring out the common factors from each group gives us \( b^3(4b - 5) + 3(4b - 5) \). Now we can see that \( (4b - 5) \) is a common factor, leading to the final factored form: \( (4b - 5)(b^3 + 3) \). So, the answer will be: \( (4b - 5)(b^3 + 3) \)

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