Solve for \( x \) \[ 13^{8 x}=6^{-x-3} \] Round your answer to the nearest thousandth. Do not round any intermediate computations.
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To solve the equation \( 13^{8x} = 6^{-x-3} \), we will take the logarithm of both sides. We can use either natural logarithm (\(\ln\)) or common logarithm (\(\log\)). Here, we will use natural logarithm: 1. Taking \(\ln\) on both sides: \[ \ln(13^{8x}) = \ln(6^{-x-3}) \] 2. Using the power rule of logarithms: \[ 8x \ln(13) = (-x - 3) \ln(6) \] 3. Expanding the right side: \[ 8x \ln(13) = -x \ln(6) - 3 \ln(6) \] 4. Rearranging to isolate terms with \(x\): \[ 8x \ln(13) + x \ln(6) = -3 \ln(6) \] 5. Factoring out \(x\): \[ x(8 \ln(13) + \ln(6)) = -3 \ln(6) \] 6. Solving for \(x\): \[ x = \frac{-3 \ln(6)}{8 \ln(13) + \ln(6)} \] 7. Now, we will compute the values of \(\ln(6)\) and \(\ln(13)\): Using calculator approx: \(\ln(6) \approx 1.791759469\) \(\ln(13) \approx 2.564949357\) 8. Substituting these values into the equation for \(x\): \[ x = \frac{-3(1.791759469)}{8(2.564949357) + 1.791759469} \] Calculating \(8 \ln(13)\): \[ 8 \cdot 2.564949357 \approx 20.519594856 \] Adding \(\ln(6)\): \[ 20.519594856 + 1.791759469 \approx 22.311354325 \] 9. Now substituting into our equation for \(x\): \[ x = \frac{-3(1.791759469)}{22.311354325} \] Calculating the numerator: \[ -3 \cdot 1.791759469 \approx -5.375278407 \] Thus, \[ x \approx \frac{-5.375278407}{22.311354325} \approx -0.2415637811 \] 10. Rounding to the nearest thousandth: \[ x \approx -0.242 \] Thus, the final answer is \[ \boxed{-0.242} \]
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