1. Find the answers. Show all your a. \( 2 \frac{2}{3}+1 \frac{1}{2}+3 \frac{3}{4}= \)

To solve \( 2 \frac{2}{3}+1 \frac{1}{2}+3 \frac{3}{4} \), we first convert each mixed number to an improper fraction: 1. \( 2 \frac{2}{3} = \frac{8}{3} \) 2. \( 1 \frac{1}{2} = \frac{3}{2} \) 3. \( 3 \frac{3}{4} = \frac{15}{4} \) Now, we find a common denominator to add these fractions. The least common multiple of 3, 2, and 4 is 12. Now, we convert each fraction: - \( \frac{8}{3} = \frac{32}{12} \) (since \( 8 \times 4 = 32 \)) - \( \frac{3}{2} = \frac{18}{12} \) (since \( 3 \times 6 = 18 \)) - \( \frac{15}{4} = \frac{45}{12} \) (since \( 15 \times 3 = 45 \)) Next, we add them: \[ \frac{32}{12} + \frac{18}{12} + \frac{45}{12} = \frac{32 + 18 + 45}{12} = \frac{95}{12} \] Now, we convert it back to a mixed number: \[ \frac{95}{12} = 7 \frac{11}{12} \] So, the final answer is \( 7 \frac{11}{12} \).