1.2 R126,00 decreased in the ratio \( 3: 7 \) is .... A. R37,80 B. R12,60 C. R294 D. R54

We are told that when R126,00 is decreased, the amount by which it is decreased and what remains are in the ratio 3:7. In other words, if d is the decrease and r is the remaining amount, then   d : r = 3 : 7 Since the total amount is the sum of these two parts, we have   d + r = R126,00 Step 1. Express r in terms of d using the ratio:   d / r = 3/7 ⟹ r = (7/3)·d Step 2. Substitute r into the total:   d + (7/3)·d = 126   (1 + 7/3)·d = 126   (3/3 + 7/3)·d = 126   (10/3)·d = 126 Step 3. Solve for d:   d = 126 × (3/10)   d = 378/10   d = R37,80 Thus, the amount by which R126,00 is decreased in the ratio 3:7 is R37,80. The correct answer is Option A.