Given the function \( p(c)=c^{2}+c \), complete the following. (a) Evaluate \( p(-5) \). (b) Solve \( p(c)=2 \). (Enter your answers as a comma-separated list.) \( c=\square \)

**(a)** We substitute \( c = -5 \) into the function: \[ p(-5) = (-5)^2 + (-5) = 25 - 5 = 20. \] **(b)** To solve \( p(c) = 2 \) we set up the equation: \[ c^2 + c = 2. \] Subtract 2 from both sides to obtain: \[ c^2 + c - 2 = 0. \] We factor the quadratic by finding two numbers that multiply to \(-2\) and add to \(1\). These numbers are \(2\) and \(-1\): \[ c^2 + c - 2 = (c + 2)(c - 1) = 0. \] Setting each factor equal to zero gives: \[ c + 2 = 0 \quad \Rightarrow \quad c = -2, \] \[ c - 1 = 0 \quad \Rightarrow \quad c = 1. \] Thus, the solutions are: \[ c = -2, \, 1. \]