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Match the operation with its inverse operation you would use to solve an equation for a vari

Ask by Tran Delgado. in the United States
Mar 17,2025

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To solve an equation for a variable, use the inverse operation: - **Addition** → **Subtraction** - **Subtraction** → **Addition** - **Multiplication** → **Division** - **Division** → **Multiplication** - **Exponentiation** → **Root Extraction** - **Root Extraction** → **Exponentiation**

Solución

- To undo an addition, you subtract. For example, if you have \[ x + a = b, \] you subtract \( a \) from both sides to get \[ x = b - a. \] - To undo a subtraction, you add. For instance, if \[ x - a = b, \] you add \( a \) to both sides to obtain \[ x = b + a. \] - To undo a multiplication, you divide. For example, if \[ a \cdot x = b, \] you divide both sides by \( a \) to get \[ x = \frac{b}{a}. \] - To undo a division, you multiply. For instance, if \[ \frac{x}{a} = b, \] you multiply both sides by \( a \) so that \[ x = a \cdot b. \] - To undo an exponentiation, you take a root. For example, if \[ x^n = a, \] you take the \( n \)th root of both sides: \[ x = \sqrt[n]{a}. \] - Conversely, to undo a root extraction, you raise both sides to the corresponding power. For instance, if \[ \sqrt[n]{x} = a, \] raising both sides to the \( n \)th power yields \[ x = a^n. \]

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Extra Insights

When you're solving equations, matching operations with their inverses is like pairing dance partners — they complement each other perfectly! For instance, if you're dealing with addition, its inverse is subtraction. So, if you have an equation like \( x + 5 = 12 \), you would subtract 5 from both sides to isolate \( x \). Similarly, multiplication pairs beautifully with division! If your equation is \( 3x = 12 \), you'd divide both sides by 3 to solve for \( x \). Understanding these partnerships makes solving equations straightforward and, dare we say, fun!

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