\( \begin{array}{lll}\text { Calculate: } & \text { (b) } \frac{2}{3}-\frac{1}{3}+\frac{1}{2} & \text { (c) } \frac{4}{3}+\frac{2}{9}+\frac{3}{4} \\ \text { (a) } \frac{1}{5}+\frac{1}{3} \times \frac{1}{2} & \text { (c) } 2 \frac{3}{4}-1 \frac{1}{2} \times 1 \frac{2}{3} & \text { (1) } 2 \frac{1}{4}+13 \frac{1}{2}-2\end{array} \)

To tackle fraction problems, always start by finding a common denominator when you’re adding or subtracting fractions. For example, for part (b), the common denominator for \( \frac{2}{3} \), \( \frac{1}{3} \), and \( \frac{1}{2} \) is 6. Rewrite the fractions as \( \frac{4}{6} \), \( \frac{2}{6} \), and \( \frac{3}{6} \) respectively. After you simplify the arithmetic, you should find the answer is \( \frac{5}{6} \). Now, for part (c), again look for a common denominator (which this time can be 36). Rewrite \( \frac{4}{3} \) as \( \frac{48}{36} \), \( \frac{2}{9} \) as \( \frac{8}{36} \), and \( \frac{3}{4} \) as \( \frac{27}{36} \). When you add them together, you get \( \frac{83}{36} \), or as a mixed number, \( 2 \frac{11}{36} \). Keep practicing with fractions, and you’ll become a pro!