On a snow day, Matthew created two snowmen in his backyard. Snowman A was built to a height of 33 inches and Snowman B was built to a height of 53 inches. The next day, the temperature increased and both snowmen began to melt. At sunrise, Snowman A's height decrease by 5 inches per hour and Snowman B's height decreased by 10 inches per hour. Let represent the height of Snowman A \( t \) hours after sunrise and let \( B \) represent the height of Snowman B \( t \) hours after sunrise. Write an equation for each situation, in terms of \( t \), and determine the interval of time, \( t \), when Snowman A is taller than Snowman B.
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Sure! Let's start by drafting those equations based on the diminishing heights of the snowmen: For Snowman A: \[ A(t) = 33 - 5t \] For Snowman B: \[ B(t) = 53 - 10t \] Next, to find the interval when Snowman A is taller than Snowman B, we set up the inequality: \[ 33 - 5t > 53 - 10t \] Solving this gives: 1. Add \( 10t \) to both sides: \[ 33 + 5t > 53 \] 2. Subtract 33 from both sides: \[ 5t > 20 \] 3. Divide by 5: \[ t > 4 \] Now, we also need to consider when both snowmen reach a height of 0. For Snowman A: \[ 0 = 33 - 5t \quad \Rightarrow \quad 5t = 33 \quad \Rightarrow \quad t = 6.6 \text{ hours} \] For Snowman B: \[ 0 = 53 - 10t \quad \Rightarrow \quad 10t = 53 \quad \Rightarrow \quad t = 5.3 \text{ hours} \] Thus, Snowman A is taller than Snowman B in the interval: \[ 4 < t < 5.3 \text{ hours} \] So, if you want to see who stands taller on the snow day, Snowman A holds the crown between these precious hours!
