Solve. Round to the nearest tenth of a percent. According to a country's census, there were 32.1 million citizens living in poverty in 2001. By 2009, the number had increased to 43.1 million. Find the percent increase in the number of citizens living in poverty from 2001 to 2009 . \( \square \% \)

To find the percent increase in the number of citizens living in poverty from 2001 to 2009, we can follow these steps: 1. **Identify the initial and final values:** - Initial value (2001): \( P_1 = 32.1 \) million - Final value (2009): \( P_2 = 43.1 \) million 2. **Calculate the increase in the number of citizens living in poverty:** \[ \text{Increase} = P_2 - P_1 = 43.1 - 32.1 \] 3. **Calculate the percent increase:** \[ \text{Percent Increase} = \left( \frac{\text{Increase}}{P_1} \right) \times 100 \] Now, let's perform the calculations step by step. First, we calculate the increase: \[ \text{Increase} = 43.1 - 32.1 \] Next, we will calculate the percent increase using the formula above. Let's compute these values. Calculate the value by following steps: - step0: Calculate: \(43.1-32.1\) - step1: Subtract the numbers: \(11\) Calculate or simplify the expression \( (43.1 - 32.1) / 32.1 * 100 \). Calculate the value by following steps: - step0: Calculate: \(\frac{\left(43.1-32.1\right)}{32.1}\times 100\) - step1: Remove the parentheses: \(\frac{43.1-32.1}{32.1}\times 100\) - step2: Subtract the numbers: \(\frac{11}{32.1}\times 100\) - step3: Divide the terms: \(\frac{110}{321}\times 100\) - step4: Multiply: \(\frac{110\times 100}{321}\) - step5: Multiply: \(\frac{11000}{321}\) 1. **Calculate the increase:** \[ \text{Increase} = 43.1 - 32.1 = 11 \text{ million} \] 2. **Calculate the percent increase:** \[ \text{Percent Increase} = \left( \frac{11}{32.1} \right) \times 100 \approx 34.3\% \] Thus, the percent increase in the number of citizens living in poverty from 2001 to 2009 is approximately \( \boxed{34.3\%} \).