Find the measure of each exterior angle of each regular polygon. 10. quadrilateral 11. octagon

For a quadrilateral, which has four sides, the measure of each exterior angle can be found using the formula \( \frac{360^\circ}{n} \) where \( n \) is the number of sides. So, \( \frac{360^\circ}{4} = 90^\circ \). Each exterior angle of a regular quadrilateral (like a square) measures 90 degrees! For an octagon, with eight sides, we use the same formula. Therefore, \( \frac{360^\circ}{8} = 45^\circ \). So, each exterior angle in a regular octagon measures 45 degrees. Isn’t it neat how polygons have such predictable angle measures?