2. Solve the simultaneous equations \( 3 x+4 y=23 \) \( 2 x-4 y=2 \)
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The Deep Dive
To solve the simultaneous equations, we can use the substitution or elimination method. Let's use the elimination method here. First, we can add both equations to eliminate \(y\): 1. \(3x + 4y = 23\) 2. \(2x - 4y = 2\) Adding these, we get: \((3x + 4y) + (2x - 4y) = 23 + 2\) This simplifies to: \(5x = 25\) Now, divide both sides by 5: \(x = 5\) Next, substitute \(x = 5\) back into one of the original equations to find \(y\). We'll use the first equation: \(3(5) + 4y = 23\) This simplifies to: \(15 + 4y = 23\) Now, subtract 15 from both sides: \(4y = 8\) Dividing by 4, we find: \(y = 2\) Thus, the solution to the simultaneous equations is \(x = 5\) and \(y = 2\).
