$$ 2.4 \begin{array}{cc}2(-3)-(5)-4(6 \div(-3)) \ ext { A } & 5-6 \ ext { B } & 22 \ ext { C } & 19 \ ext { D } & 9\end{array}= $$

Question

$$ 2.4 \begin{array}{cc}2(-3)-(5)-4(6 \div(-3)) \ 	ext { A } & 5-6 \ 	ext { B } & 22 \ 	ext { C } & 19 \ 	ext { D } & 9\end{array}= $$

UpStudy AI · Accepted Answer

We wish to simplify the expression

$$
2(-3)-5-4\Bigl(6\div(-3)\Bigr).
$$

Step 1. Multiply $$2$$ by $$-3$$:

$$
2(-3)=-6.
$$

Step 2. Compute the division inside the parentheses:

$$
6\div(-3)=-2.
$$

Step 3. Multiply $$4$$ by the result of the division:

$$
4(-2)=-8.
$$

Step 4. Substitute the computed values back into the expression:

$$
-6-5-(-8).
$$

Step 5. Note that subtracting a negative number is equivalent to adding the positive number. Thus we have

$$
-6-5+8.
$$

Step 6. Combine the numbers step by step:

$$
-6-5=-11,
$$
$$
-11+8=-3.
$$

Thus, the value of the expression is

$$
-3.
$$
The value of the expression is $$-3$$.

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