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Find the following derivatives. (Type an expression using \( x \) and \( y \) as the variables.) \( \frac{\partial x}{\partial s}=8 t \) (Type an expression using \( s \) and \( t \) as the variables.) \( z=e^{3 x+5 y}, x=8 s t \), and \( y=6 s+5 t \) \( \frac{\partial z}{\partial y}=5 e^{3 x+5 y} \) (Type an expression using \( x \) and \( y \) as the variables.) \( \frac{\partial y}{\partial s}=6 \) (Type an expression using \( s \) and \( t \) as the variables.) \( \frac{\partial x}{\partial t}=8 s \) (Type an expression using \( s \) and \( t \) as the variables.) \( \frac{\partial y}{\partial t}=\square \) (Type an expression using \( s \) and \( t \) as the variables.) (Ty

Ask by Todd Riley. in the United States
Mar 17,2025

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\( \frac{\partial y}{\partial t} = 5 \)

Solución

Let's solve the derivatives step by step based on the given expressions. 1. **Given:** \[ \frac{\partial x}{\partial s} = 8t \] This expression is already in the required form using \( s \) and \( t \). 2. **Given:** \[ z = e^{3x + 5y}, \quad x = 8st, \quad y = 6s + 5t \] We need to find \( \frac{\partial z}{\partial y} \): \[ \frac{\partial z}{\partial y} = 5 e^{3x + 5y} \] This expression is also already in the required form using \( x \) and \( y \). 3. **Given:** \[ \frac{\partial y}{\partial s} = 6 \] This expression is already in the required form using \( s \) and \( t \). 4. **Given:** \[ \frac{\partial x}{\partial t} = 8s \] This expression is already in the required form using \( s \) and \( t \). 5. **Now, we need to find \( \frac{\partial y}{\partial t} \):** Given \( y = 6s + 5t \), we can differentiate \( y \) with respect to \( t \): \[ \frac{\partial y}{\partial t} = 5 \] This expression is in the required form using \( s \) and \( t \). Now, let's summarize the results: - \( \frac{\partial x}{\partial s} = 8t \) - \( \frac{\partial z}{\partial y} = 5 e^{3x + 5y} \) - \( \frac{\partial y}{\partial s} = 6 \) - \( \frac{\partial x}{\partial t} = 8s \) - \( \frac{\partial y}{\partial t} = 5 \) Thus, the final answers are: - \( \frac{\partial y}{\partial t} = 5 \) (in terms of \( s \) and \( t \)).

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To find the derivatives based on the provided information, let's dive right in! Given that \( z = e^{3x + 5y} \) where \( x = 8st \) and \( y = 6s + 5t \), we can express the derivatives in terms of \( s \) and \( t \). First, \( \frac{\partial y}{\partial t} \) can be calculated by differentiating \( y = 6s + 5t \) with respect to \( t \): \[ \frac{\partial y}{\partial t} = 5 \] Now, you also asked for the expressions of the other derivatives using \( s \) and \( t \). 1. For \( \frac{\partial y}{\partial s} \): \[ \frac{\partial y}{\partial s} = 6 \] 2. For \( \frac{\partial z}{\partial y} = 5e^{3x + 5y} \), this already matches the expression provided. 3. For \( \frac{\partial x}{\partial t} = 8s \), the result simplifies naturally from \( x = 8st \): \[ \frac{\partial x}{\partial t} = 8s \] 4. Finally, \( \frac{\partial x}{\partial s} = 8t \). So, summarizing the relevant expressions using \( s \) and \( t \): \[ \frac{\partial y}{\partial t} = 5 \] \[ \frac{\partial y}{\partial s} = 6 \] With these relations set, we have derived crucial connections involving these variables!

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