*. Algebra The solution to the linear system \( x=-3, y=m x-\frac{7}{2} \) is \( (-3,1) \). What is the value of \( m \) ?
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To find the value of \( m \), we substitute \( x = -3 \) into the equation \( y = m x - \frac{7}{2} \). Since we know that the solution is \( (-3, 1) \), we can set \( y = 1 \). Thus, the equation becomes: \[ 1 = m(-3) - \frac{7}{2} \] Rearranging gives: \[ 1 + \frac{7}{2} = -3m \] Converting \( 1 \) to a fraction gives \( \frac{2}{2} \), so: \[ \frac{2}{2} + \frac{7}{2} = -3m \] This simplifies to: \[ \frac{9}{2} = -3m \] Dividing both sides by -3 leads to: \[ m = -\frac{3}{9} = -\frac{1}{3} \] Thus, the value of \( m \) is \( -\frac{1}{3} \).
