Joxon must sell at least 49 rolls of wrapping paper to support the robotics club fundraiser. He has already sold 24 rolls of wrapping paper. Which inequality best represents the number of rolls of wrapping paper Jaxon still needs to sell? \( \begin{array}{ll}\text { A. } x+24>49 & \text { B. } x+24 \leq 49 \\ \text { C. } x+24<49 & \text { D. } x+24 \geq 49\end{array} \)
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Bonus Knowledge
To find out how many more rolls of wrapping paper Jaxon needs to sell, you can start by setting up the inequality. Since he has already sold 24 rolls and needs to sell at least 49, you'll want to represent the number of rolls he still needs to sell as \( x \). The correct equation would be \( x + 24 \geq 49 \), meaning he must sell enough rolls to reach or exceed the total required. So, the answer is D: \( x + 24 \geq 49 \). If you're looking to find the number of additional sales needed, don't forget to isolate \( x \) in the inequality! By subtracting 24 from both sides, you'll discover that \( x \geq 25 \), showing Jaxon needs to sell at least 25 more rolls. This serves as a great reminder that careful manipulation of inequalities can lead you to the solution!
