Follow the proper order of operations to evaluate the following. \( \frac{-3\left(4^{3}-56\right)}{7-15} \)

To tackle this problem, we should follow the order of operations, often remembered by the acronym PEMDAS (Parentheses, Exponents, Multiplication and Division (from left to right), Addition and Subtraction (from left to right)). First, let's simplify what's inside the parentheses: 1. Calculate \( 4^3 \) which is \( 64 \). 2. Then, perform \( 64 - 56 \) to get \( 8 \). Now the expression looks like this: \[ \frac{-3(8)}{7 - 15} \] Next up, we handle the denominator \( 7 - 15 \), which equals \( -8 \). So our expression now reads: \[ \frac{-3(8)}{-8} \] Next, multiply \(-3\) and \(8\) to arrive at \(-24\): \[ \frac{-24}{-8} \] Finally, divide \(-24\) by \(-8\), which results in \(3\). The final answer is \( 3 \).