in the bubble completely to show your ans Alanso had s515.97 in his savings account at the beginning of the month. At the end of the month he had \( \$ 642.47 \) in the account. If Alanso withdrew no money that month, how much money did he deposit into his savings account that month? \( \begin{array}{ll}\text { (A) } \$ 133.50 & \text { (C) } 51,1.3 .34 \\ \text { (B) } 51,164.44 & \text { (D) } \$ 132.50\end{array} \)

To find out how much money Alanso deposited into his savings account during the month, we can set up the following equation based on the information provided: 1. **Initial amount in the account**: \( S_i = 515.97 \) 2. **Final amount in the account**: \( S_f = 642.47 \) 3. **Amount deposited**: \( D \) Since Alanso did not withdraw any money, the relationship between these amounts can be expressed as: \[ S_f = S_i + D \] Now, we can rearrange this equation to solve for \( D \): \[ D = S_f - S_i \] Substituting the known values: \[ D = 642.47 - 515.97 \] Now, let's calculate \( D \). \[ D = 642.47 - 515.97 = 126.50 \] Now, let's check the options provided: - (A) \( \$ 133.50 \) - (B) \( \$ 164.44 \) - (C) \( \$ 131.34 \) - (D) \( \$ 132.50 \) The calculated deposit amount \( D = 126.50 \) does not match any of the options provided. It seems there might be a mistake in the options or the calculation. Let's double-check the calculation: \[ D = 642.47 - 515.97 = 126.50 \] The calculation is correct. Therefore, Alanso deposited \( \$ 126.50 \) into his savings account that month, which is not listed among the options.