\( 1 \leftarrow \) Find the zeros for the polynomial function and give the multiplicity for each zero. State whether the graph crosses ti \( f(x)=x^{3}+2 x^{2}-9 x-18 \) Determine the zero(s), if they exist. The zero(s) is/are f. (Type integers or decimals. Use a comma to separate answers as needed.)

First, let's find the zeros of the polynomial \( f(x) = x^{3} + 2x^{2} - 9x - 18 \) using the Rational Root Theorem. Testing possible rational roots, we find that \( x = 2 \) is a zero. By synthetic division, we divide the polynomial by \( x - 2 \) to get \( x^{2} + 4x + 9 \). The quadratic has no real roots, but we can find complex roots through the quadratic formula, leading us to \( x = -2 \pm 3i \). So, the zeros are \( 2 \) (with multiplicity 1) and \( -2 \pm 3i \) (each with multiplicity 1). The graph crosses the x-axis at \( x = 2 \), but does not cross at the complex roots since they don't represent points on the graph.