Find the pair of integers whose product and sum are given. Product: \( -12 \quad \) Sum: -1 The integers are \( \square \) and \( \square \)

To find the pair of integers, we can set up two equations based on the product and sum: Let the integers be \( x \) and \( y \). We have: 1. \( x \cdot y = -12 \) 2. \( x + y = -1 \) Now, we can express \( y \) in terms of \( x \) using the sum equation: \( y = -1 - x \) Substituting into the product equation gives us: \( x(-1 - x) = -12 \) This simplifies to: \( -x - x^2 = -12 \) or \( x^2 + x - 12 = 0 \) Next, we can factor the quadratic equation: \( (x + 4)(x - 3) = 0 \) Thus, the solutions for \( x \) are: \( x = -4 \) or \( x = 3 \) If \( x = -4 \), then \( y = -1 - (-4) = 3 \). If \( x = 3 \), then \( y = -1 - 3 = -4 \). Hence, the integers are \( -4 \) and \( 3 \).