Solve using substitution. \[ \begin{array}{l}y=-3 x-2 \\ y=3 x+10\end{array} \]

Let’s substitute the expression for \( y \) from the first equation into the second equation. So, from \( y = -3x - 2 \), we replace \( y \) in the second equation: \[ -3x - 2 = 3x + 10 \] Now, let's solve for \( x \): \[ -3x - 2 - 3x = 10 \\ -6x - 2 = 10 \\ -6x = 10 + 2 \\ -6x = 12 \\ x = \frac{12}{-6} \\ x = -2 \] Now that we have \( x \), let’s find \( y \) by substituting \( x \) back into the first equation: \[ y = -3(-2) - 2 \\ y = 6 - 2 \\ y = 4 \] So, the solution to the system of equations is \( (x, y) = (-2, 4) \).