(1)) Find the quotient. \( -3 \frac{1}{2} \div 2 \frac{1}{3}=\square ? \) \( ? \)

To find the quotient of \( -3 \frac{1}{2} \div 2 \frac{1}{3} \), first convert the mixed numbers to improper fractions. For \( -3 \frac{1}{2} \): Multiply the whole number by the denominator and add the numerator: \( -3 \times 2 + 1 = -6 + 1 = -5 \) So, it becomes \( \frac{-7}{2} \). For \( 2 \frac{1}{3} \): Multiply the whole number by the denominator and add the numerator: \( 2 \times 3 + 1 = 6 + 1 = 7 \) So, it becomes \( \frac{7}{3} \). Now, divide \( \frac{-7}{2} \) by \( \frac{7}{3} \) by multiplying by the reciprocal: \( \frac{-7}{2} \times \frac{3}{7} = \frac{-7 \cdot 3}{2 \cdot 7} = \frac{-21}{14} \). Finally, simplify \( \frac{-21}{14} \) to \( -\frac{3}{2} \) or \( -1 \frac{1}{2} \). So, the final answer is: \[ -1 \frac{1}{2} \]